Perpendicular Tube

Physics Question?

Up near Truckie, the Schmidt boys are inner tubing down a snow covered creek bed. Fred and his tube weigh 225 pounds together. The creek bed is a 20 degree incline. How fast will Fred be gping at the end of a 30 meter run? Find force parallel, force perpendicular, and acceleration as well.

Please show/explain all work. Please show all formulas used.

Let:
m be the mass of the Scmidt boys and their tube,
R be the normal reaction of the incline,
t be the inclination of the run to the horizontal,
a be the acceleration down the inclne,
g be the acceleration due to gravity,
s be the length of the run,
v be the velocity at the end of the run.

Provided there is no friction, resolving parallel and perpendicular to the incline:
mg sin(t) = ma ...(1)
mg cos(t) = R ...(2)

The final speed is given by:
v^2 = 2as ...(3)

The left hand side of (1) gives the force parallel to the incline:
225 * 9.81 * sin(20)
= 754.9 N.

The acceleration is:
a = 9.81 * sin(20)
= 3.36 m/s^2.

The LHS of (2) gives the force perpendicular:
225 * 9.81 * cos(20)
= 2074.1 N.

(3) gives:
v = sqrt(2 * 3.36 * 30)
= 14.2 m/s.

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